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Concept - Percentage



DEFINITION:-

A fraction whose denominator is 100 is called a percentage & the denominator of the fraction is called the rate of percent (%).

 

PERCENT (%) :

The word  percent is an abbreviation of the lain phrase ‘percentum’  which means per hundred or hundredths. A trader makes a profit of 20% means that he gains Rs.20  on every hundred rupees of his investment. A boy scored 70 % marks in his final examination means that he obtained 70 marks out of every hundred marks.

 

Percent as a Fraction:-

1)35% = 35/100 = 7/20
2)12% = 12/100 = 3/25

 

Percent in decimal form:-

1)65% = 65/100 = 0.65
2)73% = 73/100 = 0.73

 

Eg:1)A man spends 92% of his monthly income. If he saves Rs.220/- per month, what is his monthly income ?

Solution:- A man spends 92% of his income means he saves the remaining 8% of his income.
Thus 8% = 220
If 8% = 220 then 100% = ? 100/8 * 220 = 2750

 

 

Eg:2)In school 720 are boys and 40% are girls. Find the number of girls?

Solution:- 40% are girls means remaining 60% are boys
If 60%=720 then 40% =? 40/60 * 720 = 480

 

Eg:3)Find 8% of Rs.625

Solution:- 8% of 625 = 8/100 * 625 = Rs.50/-

 

 

Eg : 4)The population of a town has increased from 50,000 to 60,000. Find the increase %?

Solution:-%increase = 10,000 / 50,000 * 100 = 20%

 

Some important Rules:

 

1.If ‘A’ is R% more than B, then;

  ‘B’ is less than A by : 

 

2.If ‘A’ is R% Less than B, then;

'B' is more than A by ;

 

3.The Price of a commodity increases by R% then reduce in consumption not to increase the expenditure is

 

4.If the price of a commodity decreases by R% then the increase in consumption not be decrease the expenditure is

 

Rules on Population:-

Let the present population of a town be ‘P’ now and suppose it increases at the rate of R% p.a., then,

 

i)Population after ‘n’ years =

 

ii)Population  ‘n’ years ago =

 

Results on decreciation:-

Let the present value of a machine be ‘P’ now and suppose it depreciates at the rate of R% p.a. then

i)Value of the machine after ‘n’ years =

 

ii)Value of the machine ‘n’ years ago =

 

Results on increases & decreases of the two values:-

1.If the value is increased successively x% and y% then the final increase is given by :

 

2. If the value of a number is first increased by x% and later decreased by y%, then there is %increase / decrease according to the sign value

 

3.If the value of a number is first increased by x% and later decreased by x%, then the net change is always decrease, which is equal to

 

4.If the value is decreased successively x% & y% then final decrease is given by :

 

 

Important Theorem :-

 

If the sides of a triangle, rectangle, square, circle, rhombus (or any two – dimensional figure) are

 

i)increased by x%, its area is increased by :

 

ii)decreased by x%, its area is decreased by :

 

Practice following examples

 

1)What % of 40 minutes is 24 seconds?

2)455 ÷ 13 + ?% of 680 = 205

3)0.07% of 1180 - 0.03% of 380 = ?

4)34% of 320 + ?% of 460 = 237.6

5)7.4% of 3455 + 6.25% of 2.9328 = ?

6)A's income is 25% more than B's income. The % of B's income in terms of A's income is ?

 

Answers:

1)40x60 / 100 ( or 2400 seconds/100)=24 Seconds

2) 25; =>?% of 680 = 205 - 35; =>?=170 x 100/680 = 25 ;

3) =>0.07/100 * 1180 - 0.03/100 x 380; =>0.826-0.114=0.712;

4) =>108.8 + ? x 4.6 = 237.6; ?=237.6-108.8/4.6 = 28;

5) 274;

6) 80%;






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